4c^2+17c+4=0

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Solution for 4c^2+17c+4=0 equation:


Simplifying
4c2 + 17c + 4 = 0

Reorder the terms:
4 + 17c + 4c2 = 0

Solving
4 + 17c + 4c2 = 0

Solving for variable 'c'.

Factor a trinomial.
(4 + c)(1 + 4c) = 0

Subproblem 1

Set the factor '(4 + c)' equal to zero and attempt to solve: Simplifying 4 + c = 0 Solving 4 + c = 0 Move all terms containing c to the left, all other terms to the right. Add '-4' to each side of the equation. 4 + -4 + c = 0 + -4 Combine like terms: 4 + -4 = 0 0 + c = 0 + -4 c = 0 + -4 Combine like terms: 0 + -4 = -4 c = -4 Simplifying c = -4

Subproblem 2

Set the factor '(1 + 4c)' equal to zero and attempt to solve: Simplifying 1 + 4c = 0 Solving 1 + 4c = 0 Move all terms containing c to the left, all other terms to the right. Add '-1' to each side of the equation. 1 + -1 + 4c = 0 + -1 Combine like terms: 1 + -1 = 0 0 + 4c = 0 + -1 4c = 0 + -1 Combine like terms: 0 + -1 = -1 4c = -1 Divide each side by '4'. c = -0.25 Simplifying c = -0.25

Solution

c = {-4, -0.25}

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